What are the solutions to the equation x^2+9x+9=0 ?

The solutions to the equation x^2+9x+9=0 are x=(-9+3sqrt(5))/2 ,x=(-9-3sqrt(5))/2

Find the zeros of x^2+9x+9=0

The zeros of x^2+9x+9=0 are x=(-9+3sqrt(5))/2 ,x=(-9-3sqrt(5))/2

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x^{2} + 9 x + 9 = 0

x = \frac{- 9 + 3 5}{2}, x = \frac{- 9 - 3 5}{2}

Decimal Notation

x = - 1.14589 \dots, x = - 7.85410 \dots

Solution steps

x^{2} + 9 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 9 = 35

x_{1, 2} = \frac{- 9 \pm 3 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 3 5}{2 \cdot 1}, x_{2} = \frac{- 9 - 3 5}{2 \cdot 1}

x = \frac{- 9 + 3 5}{2 \cdot 1} : \frac{- 9 + 3 5}{2}

x = \frac{- 9 - 3 5}{2 \cdot 1} : \frac{- 9 - 3 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 3 5}{2}, x = \frac{- 9 - 3 5}{2}

z^{2} - 1 \leq 2

\frac{x ^{2}}{x - 1} > 0

- y^{2} x^{4} + \frac{4}{3} x^{3} - 2 x^{2} + 3 x - 1

\frac{2 x - 6}{x + 1} \leq 1

25 x^{2} - 100

What are the solutions to the equation x^2+9x+9=0 ?
The solutions to the equation x^2+9x+9=0 are x=(-9+3sqrt(5))/2 ,x=(-9-3sqrt(5))/2
Find the zeros of x^2+9x+9=0
The zeros of x^2+9x+9=0 are x=(-9+3sqrt(5))/2 ,x=(-9-3sqrt(5))/2