What is the answer to solvefor a,((1+i)^{75})/((1-i)^{72)}=a+b ?

The answer to solvefor a,((1+i)^{75})/((1-i)^{72)}=a+b is a=((1+i)^{75})/((1-i)^{72)}-b

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solvefor a,((1+i)^{75})/((1-i)^{72)}=a+b

solve for

a, \frac{( 1 + i ) ^{75}}{( 1 - i ) ^{72}} = a + b

a = \frac{( 1 + i ) ^{75}}{( 1 - i ) ^{72}} - b

Solution steps

\frac{( 1 + i ) ^{75}}{( 1 - i ) ^{72}} = a + b

Switch sides

a + b = \frac{( 1 + i ) ^{75}}{( 1 - i ) ^{72}}

Move

b

to the right side

a = \frac{( 1 + i ) ^{75}}{( 1 - i ) ^{72}} - b

x, y = x + p^{3}

5 (\frac{- 11 - 5 b}{2}) + 2 = 4 b - 1

x, 7 x - 10 z = 9

(x - 9) + (5 x + 3) = 180

a, 45 a + 6 b^{4} = 1098

What is the answer to solvefor a,((1+i)^{75})/((1-i)^{72)}=a+b ?
The answer to solvefor a,((1+i)^{75})/((1-i)^{72)}=a+b is a=((1+i)^{75})/((1-i)^{72)}-b