What is the answer to ((2y-1))/3-((3y+1))/4 =y-6 ?

The answer to ((2y-1))/3-((3y+1))/4 =y-6 is y=5

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((2y-1))/3-((3y+1))/4 =y-6

\frac{( 2 y - 1 )}{3} - \frac{( 3 y + 1 )}{4} = y - 6

y = 5

Solution steps

\frac{( 2 y - 1 )}{3} - \frac{( 3 y + 1 )}{4} = y - 6

\frac{2 y - 1}{3} - \frac{3 y + 1}{4} = y - 6

Multiply by LCM

4 (2 y - 1) - 3 (3 y + 1) = 12 y - 72

Expand

4 (2 y - 1) - 3 (3 y + 1) : - y - 7

- y - 7 = 12 y - 72

Move

7

to the right side

- y = 12 y - 65

Move

12 y

to the left side

- 13 y = - 65

Divide both sides by

- 13

y = 5

a, 2 a + 5 b = c

x, g = (f)^{2}

\frac{4}{16} = \frac{3}{12}

2 - 3 x = 4 + 5 x

y, (i) \cdot y = 2 x^{3} + x^{3} - x^{2} + 4 e^{x} + 10

What is the answer to ((2y-1))/3-((3y+1))/4 =y-6 ?
The answer to ((2y-1))/3-((3y+1))/4 =y-6 is y=5
Solve for y: ((2y-1))/3-((3y+1))/4 =y-6
The solution is y=5