What is the answer to solvefor c,u_{t}+((u_{x}^3))/3 =-c*u ?

The answer to solvefor c,u_{t}+((u_{x}^3))/3 =-c*u is c=-(3u_{t}+u_{x}^3)/(3u);\quad u\ne 0

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solvefor c,u_{t}+((u_{x}^3))/3 =-c*u

solve for

c, u_{t} + \frac{( u _{x}^{3} )}{3} = - c \cdot u

c = - \frac{3 u _{t} + u _{x}^{3}}{3 u}; u \neq = 0

Solution steps

u_{t} + \frac{( u _{x}^{3} )}{3} = - c u

Switch sides

- c u = u_{t} + \frac{u _{x}^{3}}{3}

- c u = u_{t} + \frac{u _{x}^{3}}{3}

Divide both sides by

- u; u \neq = 0

c = - \frac{3 u _{t} + u _{x}^{3}}{3 u}; u \neq = 0

x, 2 (x + y) - 3 x = 6

x, x + \frac{1}{2} - y + \frac{4}{11} = 2

\frac{13}{4} x - 5 = \frac{33}{1}

x, y - 10 + 2 x = 180

- 4 x - 28 = 3 x - 24

What is the answer to solvefor c,u_{t}+((u_{x}^3))/3 =-c*u ?
The answer to solvefor c,u_{t}+((u_{x}^3))/3 =-c*u is c=-(3u_{t}+u_{x}^3)/(3u);\quad u\ne 0