What is the answer to (6x+1}{3+1}=\frac{x-3)/6 ?

The answer to (6x+1}{3+1}=\frac{x-3)/6 is x=-9/16

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(6x+1}{3+1}=\frac{x-3)/6

\frac{6 x + 1}{3 + 1} = \frac{x - 3}{6}

x = - \frac{9}{16}

Decimal Notation

x = - 0.5625

Solution steps

\frac{6 x + 1}{3 + 1} = \frac{x - 3}{6}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(6 x + 1) \cdot 6 = (3 + 1) (x - 3)

Simplify

(6 x + 1) \cdot 6 = 4 (x - 3)

Expand

(6 x + 1) \cdot 6 : 36 x + 6

Expand

4 (x - 3) : 4 x - 12

36 x + 6 = 4 x - 12

Move

6

to the right side

36 x = 4 x - 18

Move

4 x

to the left side

32 x = - 18

Divide both sides by

32

x = - \frac{9}{16}

9 (x + 2) = 18

\frac{1}{3} + \frac{2}{3} x = \frac{4}{3}

\frac{2 x + 7}{2} = 3 (x + 1)

13 = 13 + u

x, y - 5 = - \frac{2}{3} x - 2

What is the answer to (6x+1}{3+1}=\frac{x-3)/6 ?
The answer to (6x+1}{3+1}=\frac{x-3)/6 is x=-9/16
Solve for x: (6x+1}{3+1}=\frac{x-3)/6
The solution is x=-9/16