What is the answer to solvefor x,((x+y))/6+(13)/y =((4-y))/6 ?

The answer to solvefor x,((x+y))/6+(13)/y =((4-y))/6 is x=-2y-(78)/y+4

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solvefor x,((x+y))/6+(13)/y =((4-y))/6

solve for

x, \frac{( x + y )}{6} + \frac{13}{y} = \frac{( 4 - y )}{6}

x = - 2 y - \frac{78}{y} + 4

Solution steps

\frac{( x + y )}{6} + \frac{13}{y} = \frac{( 4 - y )}{6}

\frac{x + y}{6} + \frac{13}{y} = \frac{4 - y}{6}

Move

\frac{13}{y}

to the right side

\frac{x + y}{6} = \frac{4 - y}{6} - \frac{13}{y}

Multiply both sides by

6

x + y = 4 - y - \frac{78}{y}

Move

y

to the right side

x = - 2 y - \frac{78}{y} + 4

x, 4 x - y + \frac{z}{2} = 0

x, pq = (6 x + 5) + (9 x)

x, 2 \frac{x}{6} + 3 \frac{y}{6} = 13

v n + 1 = v n \cdot (n + 1) (n + 3) (n + 2)^{2}

\frac{( 5 x - 7 )}{4} - \frac{( 8 x - 4 )}{5} = \frac{( 2 x - 3 )}{10}

What is the answer to solvefor x,((x+y))/6+(13)/y =((4-y))/6 ?
The answer to solvefor x,((x+y))/6+(13)/y =((4-y))/6 is x=-2y-(78)/y+4