What is the answer to solvefor x,x=e^{-2t}*u(t+1) ?

The answer to solvefor x,x=e^{-2t}*u(t+1) is x=e^{-2t}u(t+1)

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solvefor x,x=e^{-2t}*u(t+1)

solve for

x, x = e^{- 2 t} \cdot u (t + 1)

x = e^{- 2 t} u (t + 1)

Solution steps

x = e^{- 2 t} u (t + 1)

Could not simplify further

x = e^{- 2 t} u (t + 1)

2 - (- 2 (x + 1) - x - \frac{3}{2}) = 2 \frac{x}{3} - 5 x - \frac{3}{12} + 3 x

x, 5 x - 8 y = 18

x, 120 = 2 x + y

- 18 = 3, (z + 4) = 18

x = \frac{( - 4 + 4 ^{2} - 4 ( - 2 ) ( 3 ) )}{( 2 ( - 2 ) )}

What is the answer to solvefor x,x=e^{-2t}*u(t+1) ?
The answer to solvefor x,x=e^{-2t}*u(t+1) is x=e^{-2t}u(t+1)