What is the answer to (a)2^{3n}2^{-5}=2^{10} ?

The answer to (a)2^{3n}2^{-5}=2^{10} is a=2^{-3n+15}

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(a)2^{3n}2^{-5}=2^{10}

(a) 2^{3 n} 2^{- 5} = 2^{10}

a = 2^{- 3 n + 15}

Solution steps

(a) \cdot 2^{3 n} \cdot 2^{- 5} = 2^{10}

Simplify

2^{3 n} \cdot 2^{- 5} : 2^{3 n - 5}

a \cdot 2^{3 n - 5} = 2^{10}

Divide both sides by

2^{3 n - 5}

a = 2^{- 3 n + 15}

p = (3 + 2 i) (3 + i)

4 (- x - 3) + 3 = - 3 (x - 2)

\frac{( a ) 6 ^{3 n}}{( 6 ^{3} )} = 216

x, 15 r = x + v

a, 5 b - \frac{( a - b )}{4} = 3 a - \frac{5}{4}

What is the answer to (a)2^{3n}2^{-5}=2^{10} ?
The answer to (a)2^{3n}2^{-5}=2^{10} is a=2^{-3n+15}