What is the answer to solvefor x,f(x+1)=2x-4 ?

The answer to solvefor x,f(x+1)=2x-4 is x=(-4-f)/(f-2);\quad f\ne 2

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solvefor x,f(x+1)=2x-4

solve for

x, f (x + 1) = 2 x - 4

x = \frac{- 4 - f}{f - 2}; f \neq = 2

Solution steps

f (x + 1) = 2 x - 4

Expand

f (x + 1) : x f + f

x f + f = 2 x - 4

Move

f

to the right side

x f = 2 x - 4 - f

Move

2 x

to the left side

x f - 2 x = - 4 - f

Factor

x f - 2 x : x (f - 2)

x (f - 2) = - 4 - f

Divide both sides by

f - 2; f \neq = 2

x = \frac{- 4 - f}{f - 2}; f \neq = 2

bn = 7 \cdot 5^{- n}

- 2 (\frac{1}{2} x - \frac{1}{3}) + \frac{3}{2} = \frac{1}{4}

t, s + 100 = \frac{1}{2} \cdot g \cdot (t + 1) \cdot 2

3 x + 4 (x - 1) = 2 (1 - x)

y, \frac{( d ^{3} \cdot y )}{( d \cdot x ^{3} )} + y = 3 + 5 e^{x}

What is the answer to solvefor x,f(x+1)=2x-4 ?
The answer to solvefor x,f(x+1)=2x-4 is x=(-4-f)/(f-2);\quad f\ne 2