What is the answer to solvefor f,f={((a+x))/((1+x))}^{a+1+2x} ?

The answer to solvefor f,f={((a+x))/((1+x))}^{a+1+2x} is f=((a+x)/(1+x))^{a+1+2x}

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solvefor f,f={((a+x))/((1+x))}^{a+1+2x}

solve for

f, f = {\frac{( a + x )}{( 1 + x )}}^{a + 1 + 2 x}

f = (\frac{a + x}{1 + x})^{a + 1 + 2 x}

Solution steps

f = {\frac{( a + x )}{( 1 + x )}}^{a + 1 + 2 x}

Remove parentheses:

(a) = a

f = (\frac{a + x}{1 + x})^{a + 1 + 2 x}

3 x - 5 = 271 - x

(q) = 30 q + 14000

\frac{4}{9 ^{3}} \cdot \frac{4}{9 ^{- 7}} = \frac{4}{9 ^{2}} x - 1

2 e^{3} x + 4 = \frac{2}{e}

t, 2 r + t = 2

What is the answer to solvefor f,f={((a+x))/((1+x))}^{a+1+2x} ?
The answer to solvefor f,f={((a+x))/((1+x))}^{a+1+2x} is f=((a+x)/(1+x))^{a+1+2x}