What is the answer to solvefor x, x/p+y/q =1 ?

The answer to solvefor x, x/p+y/q =1 is x=p-(py)/q ;\quad p\ne 0

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solvefor x, x/p+y/q =1

solve for

x, \frac{x}{p} + \frac{y}{q} = 1

x = p - \frac{p y}{q}; p \neq = 0

Solution steps

\frac{x}{p} + \frac{y}{q} = 1

Move

\frac{y}{q}

to the right side

\frac{x}{p} = 1 - \frac{y}{q}

Multiply both sides by

p

x = p - \frac{p y}{q}; p \neq = 0

\frac{1}{20} - \frac{1}{2} = x + \frac{3}{5}

x + \frac{4}{100} + x + \frac{5}{99} + x + \frac{7}{97} = 3

x = - \frac{1}{( 3 )}, \frac{2}{( 3 )}

4 (2 x + 5) - (5 x - 4) = 27

d, d (7) = 2 x^{3} - x^{2} - 4 x + 100

What is the answer to solvefor x, x/p+y/q =1 ?
The answer to solvefor x, x/p+y/q =1 is x=p-(py)/q ;\quad p\ne 0