What is the answer to x^2+6x-2=(x+3)^2+m ?

The answer to x^2+6x-2=(x+3)^2+m is True for all x;\quad 0=m+11

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x^2+6x-2=(x+3)^2+m

x^{2} + 6 x - 2 = (x + 3)^{2} + m

True for all x; 0 = m + 11

Solution steps

x^{2} + 6 x - 2 = (x + 3)^{2} + m

Expand

(x + 3)^{2} + m : x^{2} + 6 x + 9 + m

x^{2} + 6 x - 2 = x^{2} + 6 x + 9 + m

Move

2

to the right side

x^{2} + 6 x = x^{2} + 6 x + m + 11

Subtract

x^{2} + 6 x

from both sides

x^{2} + 6 x - (x^{2} + 6 x) = x^{2} + 6 x + m + 11 - (x^{2} + 6 x)

Simplify

0 = m + 11

Both sides are equal

True for all x; 0 = m + 11

x + 1.05 x + 1.05 (1.05 x) = 30

\frac{( 2 x - 6 )}{3} = 0

x, 3 x + y = 100

\frac{( x \cdot 25 )}{4} + \frac{56}{3} = 2^{3} \cdot x

(2 x + 12) \cdot 0.2 + (x + 10) = 144

What is the answer to x^2+6x-2=(x+3)^2+m ?
The answer to x^2+6x-2=(x+3)^2+m is True for all x;\quad 0=m+11