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Popular >

1+2j+21b=-i-j-k,a=2

Solution

1 + 2 j + 21 b = - i - j - k, a = 2

Solution

b = \frac{- 3 j - i - k - 1}{21}

Solution steps

1 + 2 j + 21 b = - i - j - k

Move

2 j

to the right side

1 + 21 b = - 3 j - i - k

Move

1

to the right side

21 b = - 3 j - i - k - 1

Divide both sides by

21

b = \frac{- 3 j - i - k - 1}{21}

Popular Examples

solvefor x,f[g]+g[f]+10=0 solve for

x, f [g] + g [f] + 10 = 0

solvefor x,42txt=2125 solve for

x, 42 t x t = 2125

(4+2x)/(3-2)= x/5

\frac{4 + 2 x}{3 - 2} = \frac{x}{5}

solvefor x,2xy-3x+5y=39 solve for

x, 2 x y - 3 x + 5 y = 39

solvefor g,g(r)=-5r+13g(3)solve for

g, g (r) = - 5 r + 13 g (3)

Frequently Asked Questions (FAQ)

What is the answer to 1+2j+21b=-i-j-k,a=2 ?
The answer to 1+2j+21b=-i-j-k,a=2 is b=(-3j-i-k-1)/(21)