What are the solutions to the equation 3n^2+10n=5 ?

The solutions to the equation 3n^2+10n=5 are n=(-5+2sqrt(10))/3 ,n=-(5+2sqrt(10))/3

Find the zeros of 3n^2+10n=5

The zeros of 3n^2+10n=5 are n=(-5+2sqrt(10))/3 ,n=-(5+2sqrt(10))/3

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3 n^{2} + 10 n = 5

n = \frac{- 5 + 2 10}{3}, n = - \frac{5 + 2 10}{3}

Decimal Notation

n = 0.44151 \dots, n = - 3.77485 \dots

Solution steps

3 n^{2} + 10 n = 5

Move

5

to the left side

3 n^{2} + 10 n - 5 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 5) = 410

n_{1, 2} = \frac{- 10 \pm 4 10}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- 10 + 4 10}{2 \cdot 3}, n_{2} = \frac{- 10 - 4 10}{2 \cdot 3}

n = \frac{- 10 + 4 10}{2 \cdot 3} : \frac{- 5 + 2 10}{3}

n = \frac{- 10 - 4 10}{2 \cdot 3} : - \frac{5 + 2 10}{3}

The solutions to the quadratic equation are:

n = \frac{- 5 + 2 10}{3}, n = - \frac{5 + 2 10}{3}

- 2 x^{2} - 2 x + 12 = 0

2 x - 3 \geq - 4 x + 2

r^{2} - 16 r + 47 = - 5

x - 2 < 15

4 \times 2 - 1

What are the solutions to the equation 3n^2+10n=5 ?
The solutions to the equation 3n^2+10n=5 are n=(-5+2sqrt(10))/3 ,n=-(5+2sqrt(10))/3
Find the zeros of 3n^2+10n=5
The zeros of 3n^2+10n=5 are n=(-5+2sqrt(10))/3 ,n=-(5+2sqrt(10))/3