What is the answer to solvefor m,x-1/(x^2)+3x+2= m/x+2+n/x+1 ?

The answer to solvefor m,x-1/(x^2)+3x+2= m/x+2+n/x+1 is m=4x^2-1/x-n-x;\quad x\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor m,x-1/(x^2)+3x+2= m/x+2+n/x+1

solve for

m, x - \frac{1}{x ^{2}} + 3 x + 2 = \frac{m}{x} + 2 + \frac{n}{x} + 1

m = 4 x^{2} - \frac{1}{x} - n - x; x \neq = 0

Solution steps

x - \frac{1}{x ^{2}} + 3 x + 2 = \frac{m}{x} + 2 + \frac{n}{x} + 1

Subtract

2

from both sides

x - \frac{1}{x ^{2}} + 3 x + 2 - 2 = \frac{m}{x} + 2 + \frac{n}{x} + 1 - 2

Simplify

x - \frac{1}{x ^{2}} + 3 x = \frac{m}{x} + \frac{n}{x} + 1

Switch sides

\frac{m}{x} + \frac{n}{x} + 1 = x - \frac{1}{x ^{2}} + 3 x

Group like terms

\frac{m}{x} + \frac{n}{x} + 1 = x + 3 x - \frac{1}{x ^{2}}

Add similar elements:

x + 3 x = 4 x

\frac{m}{x} + \frac{n}{x} + 1 = 4 x - \frac{1}{x ^{2}}

Move

\frac{n}{x}

to the right side

\frac{m}{x} + 1 = 4 x - \frac{1}{x ^{2}} - \frac{n}{x}

Move

1

to the right side

\frac{m}{x} = 4 x - \frac{1}{x ^{2}} - \frac{n}{x} - 1

Multiply both sides by

x

m = 4 x^{2} - \frac{1}{x} - n - x; x \neq = 0

x, 2 x + y = z

x, f = 3 - 9 x f (5)

a, q = a csc (b) 0

a, a \cdot b = a + b - 5

g, g (s) = \frac{k}{s} (s + 1) (s + 2)

What is the answer to solvefor m,x-1/(x^2)+3x+2= m/x+2+n/x+1 ?
The answer to solvefor m,x-1/(x^2)+3x+2= m/x+2+n/x+1 is m=4x^2-1/x-n-x;\quad x\ne 0