What are the solutions to the equation 3x^2+16x-35=0 ?

The solutions to the equation 3x^2+16x-35=0 are x= 5/3 ,x=-7

Find the zeros of 3x^2+16x-35=0

The zeros of 3x^2+16x-35=0 are x= 5/3 ,x=-7

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3 x^{2} + 16 x - 35 = 0

x = \frac{5}{3}, x = - 7

Solution steps

3 x^{2} + 16 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 ( - 35 )}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 (- 35) = 26

x_{1, 2} = \frac{- 16 \pm 26}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 16 + 26}{2 \cdot 3}, x_{2} = \frac{- 16 - 26}{2 \cdot 3}

x = \frac{- 16 + 26}{2 \cdot 3} : \frac{5}{3}

x = \frac{- 16 - 26}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 7

x^{2} = 31

- 3 - \frac{1}{2}

\frac{[ ( \frac{6 - 11 x}{2} ) ]}{( x - 3 )} > \frac{- 1}{2 ( x + 12 )}

- 7 < 2 + y

7 x + 3 = 17

What are the solutions to the equation 3x^2+16x-35=0 ?
The solutions to the equation 3x^2+16x-35=0 are x= 5/3 ,x=-7
Find the zeros of 3x^2+16x-35=0
The zeros of 3x^2+16x-35=0 are x= 5/3 ,x=-7