What is the answer to solvefor a,p(x+1)=a*p(x)^b ?

The answer to solvefor a,p(x+1)=a*p(x)^b is a=(x+1)/(x^b);\quad p\ne 0

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solvefor a,p(x+1)=a*p(x)^b

solve for

a, p (x + 1) = a \cdot p (x)^{b}

a = \frac{x + 1}{x ^{b}}; p \neq = 0

Solution steps

p (x + 1) = a p x^{b}

Switch sides

a p x^{b} = p (x + 1)

Divide both sides by

p x^{b}; p \neq = 0

a = \frac{x + 1}{x ^{b}}; p \neq = 0

x, (y - 6) 2 = 6 (x - 1)

e^{4} t + 2 = 4 e^{2} - t

x, - 12 x - 4 y + 20 = 0

y, x = y - p^{2}

b, h = \frac{4}{5} b

What is the answer to solvefor a,p(x+1)=a*p(x)^b ?
The answer to solvefor a,p(x+1)=a*p(x)^b is a=(x+1)/(x^b);\quad p\ne 0