What is the answer to 3.2((2x-2))/3+((1-3x))/2 =4 ?

The answer to 3.2((2x-2))/3+((1-3x))/2 =4 is x= 169/19

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3.2((2x-2))/3+((1-3x))/2 =4

3.2 \frac{( 2 x - 2 )}{3} + \frac{( 1 - 3 x )}{2} = 4

x = \frac{169}{19}

Decimal Notation

x = 8.89473 \dots

Solution steps

3.2 \cdot \frac{( 2 x - 2 )}{3} + \frac{( 1 - 3 x )}{2} = 4

Multiply both sides by

10

\frac{32 ( 2 x - 2 )}{3} + 5 (- 3 x + 1) = 40

Multiply both sides by

3

32 (2 x - 2) + 15 (- 3 x + 1) = 120

Expand

32 (2 x - 2) + 15 (- 3 x + 1) : 19 x - 49

19 x - 49 = 120

Move

49

to the right side

19 x = 169

Divide both sides by

19

x = \frac{169}{19}

\frac{x}{7 - 5} = 7

x, f = a (x - h) 2 + k

\cdot \frac{1}{2} \cdot 2 \cdot e^{\frac{1}{2}} = \frac{2}{e}, y_{b} = 2

(3 x - 17) + 4 = 24

[4 x - 3] = 2 x + 1

What is the answer to 3.2((2x-2))/3+((1-3x))/2 =4 ?
The answer to 3.2((2x-2))/3+((1-3x))/2 =4 is x= 169/19
Solve for x: 3.2((2x-2))/3+((1-3x))/2 =4
The solution is x= 169/19