What is the answer to solvefor x,(p/q)^1-3x=(q/p)^{1/2} ?

The answer to solvefor x,(p/q)^1-3x=(q/p)^{1/2} is x=-((q/p)^{1/2}q-p)/(3q)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,(p/q)^1-3x=(q/p)^{1/2}

solve for

x, (\frac{p}{q})^{1} - 3 x = (\frac{q}{p})^{\frac{1}{2}}

x = - \frac{( \frac{q}{p} ) ^{\frac{1}{2}} q - p}{3 q}

Solution steps

(\frac{p}{q})^{1} - 3 x = (\frac{q}{p})^{\frac{1}{2}}

Move

(\frac{p}{q})^{1}

to the right side

- 3 x = (\frac{q}{p})^{\frac{1}{2}} - \frac{p}{q}

Divide both sides by

- 3

x = - \frac{( \frac{q}{p} ) ^{\frac{1}{2}} q - p}{3 q}

x, y \frac{0.1}{3} x + \frac{2}{3} y = 1

x, 6 x - \frac{y}{3} = \frac{5}{6}

2 \frac{x}{3} + \frac{42}{5} = \frac{311}{30}

(0.5) x = - 7

x, - 3 x + 21 y = - 27

What is the answer to solvefor x,(p/q)^1-3x=(q/p)^{1/2} ?
The answer to solvefor x,(p/q)^1-3x=(q/p)^{1/2} is x=-((q/p)^{1/2}q-p)/(3q)