What is the answer to solvefor x,5(1_{2}t)+2(3-x)=3(x+4)+14 ?

The answer to solvefor x,5(1_{2}t)+2(3-x)=3(x+4)+14 is x=(20)/(-5)-(5*1_{2}t)/(-5)

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solvefor x,5(1_{2}t)+2(3-x)=3(x+4)+14

solve for

x, 5 (1_{2} t) + 2 (3 - x) = 3 (x + 4) + 14

x = \frac{20}{- 5} - \frac{5 \cdot 1 _{2} t}{- 5}

Solution steps

5 (1_{2} t) + 2 (3 - x) = 3 (x + 4) + 14

5 \cdot 1_{2} t + 2 (3 - x) = 3 (x + 4) + 14

Expand

2 (3 - x) : 6 - 2 x

5 \cdot 1_{2} t + 6 - 2 x = 3 (x + 4) + 14

Expand

3 (x + 4) + 14 : 3 x + 26

5 \cdot 1_{2} t + 6 - 2 x = 3 x + 26

Move

5 \cdot 1_{2} t

to the right side

6 - 2 x = 3 x + 26 - 5 \cdot 1_{2} t

Move

6

to the right side

- 2 x = 3 x + 20 - 5 \cdot 1_{2} t

Move

3 x

to the left side

- 5 x = 20 - 5 \cdot 1_{2} t

Divide both sides by

- 5

x = \frac{20}{- 5} - \frac{5 \cdot 1 _{2} t}{- 5}

y, tan (x) - 2 x^{3} \cdot y = c

x, 2 x + \frac{3}{y} = 5

x, - 10 \cdot y - x = 7

x, 4 x - 3 y - 5 = 0

(0) r = 10

What is the answer to solvefor x,5(1_{2}t)+2(3-x)=3(x+4)+14 ?
The answer to solvefor x,5(1_{2}t)+2(3-x)=3(x+4)+14 is x=(20)/(-5)-(5*1_{2}t)/(-5)