What is (24a^2b^2+12ab^2+6a^2b)/(2ab) ?

The solution to (24a^2b^2+12ab^2+6a^2b)/(2ab) is 12ab+6b+3a

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simplify (24a^2b^2+12ab^2+6a^2b)/(2ab)

simplify

\frac{24 a ^{2} b ^{2} + 12 a b ^{2} + 6 a ^{2} b}{2 ab}

12 ab + 6 b + 3 a

Solution steps

\frac{24 a ^{2} b ^{2} + 12 a b ^{2} + 6 a ^{2} b}{2 ab}

Factor

24 a^{2} b^{2} + 12 a b^{2} + 6 a^{2} b : 6 ab (4 ab + 2 b + a)

= \frac{6 ab ( 4 ab + 2 b + a )}{2 ab}

Cancel the common factor:

a

= \frac{6 b ( 4 ab + 2 b + a )}{2 b}

Cancel the common factor:

b

= \frac{6 ( 4 ab + 2 b + a )}{2}

Divide the numbers:

\frac{6}{2} = 3

= 3 (4 ab + 2 b + a)

Expand

3 (4 ab + 2 b + a) : 12 ab + 6 b + 3 a

= 12 ab + 6 b + 3 a

(x + y)^{2} - (x - y)^{2}

- 7 + x = 32

\frac{1}{4} - \frac{3}{5}

∣ 5 - 3 x ∣ = \frac{1}{2}

\frac{- 5 x + 92}{6} = 3 x

What is (24a^2b^2+12ab^2+6a^2b)/(2ab) ?
The solution to (24a^2b^2+12ab^2+6a^2b)/(2ab) is 12ab+6b+3a