What is the answer to solvefor a,f= a/b-3c ?

The answer to solvefor a,f= a/b-3c is a=fb+3cb;\quad b\ne 0

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solvefor a,f= a/b-3c

solve for

a, f = \frac{a}{b} - 3 c

a = f b + 3 c b; b \neq = 0

Solution steps

f = \frac{a}{b} - 3 c

Switch sides

\frac{a}{b} - 3 c = f

Move

3 c

to the right side

\frac{a}{b} = f + 3 c

Multiply both sides by

b

a = f b + 3 c b; b \neq = 0

\frac{x}{2} - 4 = 8, x

x - 2 + x - 2 = 0

x + 7 - \frac{( 8 x )}{3} = \frac{17}{6} - \frac{( 5 x )}{2}

a, 12 a + b = 26

(z - 3 i) + z + 4 i^{3} = 8 i (3 i + 3 i^{2})

What is the answer to solvefor a,f= a/b-3c ?
The answer to solvefor a,f= a/b-3c is a=fb+3cb;\quad b\ne 0