What is the answer to (x-2)^2=(x-4)(x+4) ?

The answer to (x-2)^2=(x-4)(x+4) is x=5

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(x-2)^2=(x-4)(x+4)

(x - 2)^{2} = (x - 4) (x + 4)

x = 5

Solution steps

(x - 2)^{2} = (x - 4) (x + 4)

Expand

(x - 2)^{2} : x^{2} - 4 x + 4

Expand

(x - 4) (x + 4) : x^{2} - 16

x^{2} - 4 x + 4 = x^{2} - 16

Move

4

to the right side

x^{2} - 4 x = x^{2} - 20

Move

x^{2}

to the left side

- 4 x = - 20

Divide both sides by

- 4

x = 5

x, (y + 4) = - 3 (x - 3)

\frac{1}{2} a + b + 2 x = \frac{1}{2} a + \frac{1}{b} + \frac{1}{2} x

2 \frac{x}{3} - \frac{8}{3} = \frac{17}{6}

f = \frac{1}{3} (- 5) \frac{\frac{31}{17}}{2} (- 5)

x, - 3 x - 4 y = 7

What is the answer to (x-2)^2=(x-4)(x+4) ?
The answer to (x-2)^2=(x-4)(x+4) is x=5
Solve for x: (x-2)^2=(x-4)(x+4)
The solution is x=5