What is the answer to solvefor x,p(x)=2y^2-2y ?

The answer to solvefor x,p(x)=2y^2-2y is x=(2y^2-2y)/p ;\quad p\ne 0

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solvefor x,p(x)=2y^2-2y

solve for

x, p (x) = 2 y^{2} - 2 y

x = \frac{2 y ^{2} - 2 y}{p}; p \neq = 0

Solution steps

p (x) = 2 y^{2} - 2 y

Divide both sides by

p; p \neq = 0

x = \frac{2 y ^{2} - 2 y}{p}; p \neq = 0

x, \frac{( 2 x + 3 )}{( 4 y + 1 )} = 3 + 2 x - 12 y

u, 2 u + 7 v = 52

y, \frac{( d ^{2} \cdot y )}{( d \cdot x ^{2} )} - y = x - 1

f, x (x^{3} - 1) \cdot f = 1

\frac{( 5 x - 1 )}{4} - \frac{( 3 x - 1 )}{6} = \frac{32}{3}

What is the answer to solvefor x,p(x)=2y^2-2y ?
The answer to solvefor x,p(x)=2y^2-2y is x=(2y^2-2y)/p ;\quad p\ne 0