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Popular >

t(n)=4t(n/2)+n^3

Solution

t (n) = 4 t (\frac{n}{2}) + n^{3}

Solution

t = - n^{2}; n \neq = 0

Solution steps

t (n) = 4 t (\frac{n}{2}) + n^{3}

Remove parentheses:

(a) = a

t (n) = 4 t \frac{n}{2} + n^{3}

4 t \frac{n}{2} = 2 n t

t (n) = 2 n t + n^{3}

Expand

t (n) : n t

n t = 2 n t + n^{3}

Move

2 n t

to the left side

- n t = n^{3}

Divide both sides by

- n; n \neq = 0

t = - n^{2}; n \neq = 0

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x, 5 x - 3 + 2 y = 3 x + 3 - 2 y + x

2 - 11 x = 4 x + 17

2500000-2425000=0.75x-x

2500000 - 2425000 = 0.75 x - x

solvefor x,p^1xv^1=p^2xv^2 solve for

x, p^{1} x v^{1} = p^{2} x v^{2}

t(n)=4t(n/2)+n^2

t (n) = 4 t (\frac{n}{2}) + n^{2}

Frequently Asked Questions (FAQ)

What is the answer to t(n)=4t(n/2)+n^3 ?
The answer to t(n)=4t(n/2)+n^3 is t=-n^2;\quad n\ne 0