What are the solutions to the equation m^3+1=0 ?

The solutions to the equation m^3+1=0 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i

Find the zeros of m^3+1=0

The zeros of m^3+1=0 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i

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m^{3} + 1 = 0

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

Solution steps

m^{3} + 1 = 0

Move

1

to the right side

m^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

100 (1 + r)^{3} = 112.476

x^{3} - x^{2} - 1 = 0

4 x^{3} - 4 x = 0

x^{3} - 125 = 0

x^{2} x - 6 = 0

What are the solutions to the equation m^3+1=0 ?
The solutions to the equation m^3+1=0 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i
Find the zeros of m^3+1=0
The zeros of m^3+1=0 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i