What are the solutions to the equation m^3-3m^2+3m-1=0 ?

The solutions to the equation m^3-3m^2+3m-1=0 are m=1

Find the zeros of m^3-3m^2+3m-1=0

The zeros of m^3-3m^2+3m-1=0 are m=1

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m^{3} - 3 m^{2} + 3 m - 1 = 0

m = 1

Solution steps

m^{3} - 3 m^{2} + 3 m - 1 = 0

Factor

m^{3} - 3 m^{2} + 3 m - 1 : (m - 1)^{3}

(m - 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m - 1 = 0

Solve

m - 1 = 0 : m = 1

The solution is

m = 1

z^{4} = - 4

2 x^{3} - 27 x^{2} - 4 x + 7 = 0

(4 x)^{3} = (4^{3})^{3}

2 \cdot (x + 1)^{3} = - 2

(x - 1)^{4} + (x - 5)^{4} = 82

What are the solutions to the equation m^3-3m^2+3m-1=0 ?
The solutions to the equation m^3-3m^2+3m-1=0 are m=1
Find the zeros of m^3-3m^2+3m-1=0
The zeros of m^3-3m^2+3m-1=0 are m=1