What is the answer to 3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0 ?

The answer to 3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0 is x=5

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3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0

3 x (x - 3) + 5 (x + 7) - x (x + 1) - 2 (x^{2} + 7) + 4 = 0

x = 5

Solution steps

3 x (x - 3) + 5 (x + 7) - x (x + 1) - 2 (x^{2} + 7) + 4 = 0

Move

4

to the right side

3 x (x - 3) + 5 (x + 7) - x (x + 1) - 2 (x^{2} + 7) = - 4

Expand

3 x (x - 3) + 5 (x + 7) - x (x + 1) - 2 (x^{2} + 7) : - 5 x + 21

- 5 x + 21 = - 4

Move

21

to the right side

- 5 x = - 25

Divide both sides by

- 5

x = 5

\frac{13}{2} - 5

\frac{1}{- \frac{1}{3}}

5 - \frac{3}{4} x \leq - 4

∣ x - 3 ∣ = 0.03

x^{3} + y^{3} + x^{2} y + x y^{2}

What is the answer to 3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0 ?
The answer to 3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0 is x=5
Solve for x: 3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0
The solution is x=5