What are the solutions to the equation (x-3)^3+3-x=0 ?

The solutions to the equation (x-3)^3+3-x=0 are x=2,x=3,x=4

Find the zeros of (x-3)^3+3-x=0

The zeros of (x-3)^3+3-x=0 are x=2,x=3,x=4

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(x - 3)^{3} + 3 - x = 0

x = 2, x = 3, x = 4

Solution steps

(x - 3)^{3} + 3 - x = 0

Expand

(x - 3)^{3} + 3 - x : x^{3} - 9 x^{2} + 26 x - 24

x^{3} - 9 x^{2} + 26 x - 24 = 0

Factor

x^{3} - 9 x^{2} + 26 x - 24 : (x - 2) (x - 3) (x - 4)

(x - 2) (x - 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 3 = 0 or x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 3 = 0 : x = 3

Solve

x - 4 = 0 : x = 4

The solutions are

x = 2, x = 3, x = 4

m^{3} + 6 m^{2} + 11 m + 6 = 0

x^{4} - 25 x^{2} + 144 = 0

(3 x + 1)^{3} = - 27

(1 - x)^{5} = \frac{7}{10}

x^{3} - 64 = 0

What are the solutions to the equation (x-3)^3+3-x=0 ?
The solutions to the equation (x-3)^3+3-x=0 are x=2,x=3,x=4
Find the zeros of (x-3)^3+3-x=0
The zeros of (x-3)^3+3-x=0 are x=2,x=3,x=4