What are the solutions to the equation solvefor x,(3x+7)^5=2y^3 ?

The solutions to the equation solvefor x,(3x+7)^5=2y^3 are x=(\sqrt[5]{2}\sqrt[5]{y^3}-7)/3

Find the zeros of solvefor x,(3x+7)^5=2y^3

The zeros of solvefor x,(3x+7)^5=2y^3 are x=(\sqrt[5]{2}\sqrt[5]{y^3}-7)/3

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solve for

x, (3 x + 7)^{5} = 2 y^{3}

Solution steps

(3 x + 7)^{5} = 2 y^{3}

For

(g (x))^{n} = f (a)

, n is odd, the solution is

Solve

The solution is

x^{4} + x^{3} + x^{2} + x + 1 = 0

(x + 2)^{3} = 2 x (x^{2} - 1)

x^{3} + 2 x - 12 = 0

t^{10} = 5 t^{2} - 3 t

x (x + 1) (x + 2) (x + 3) = 24

What are the solutions to the equation solvefor x,(3x+7)^5=2y^3 ?
The solutions to the equation solvefor x,(3x+7)^5=2y^3 are x=(\sqrt[5]{2}\sqrt[5]{y^3}-7)/3
Find the zeros of solvefor x,(3x+7)^5=2y^3
The zeros of solvefor x,(3x+7)^5=2y^3 are x=(\sqrt[5]{2}\sqrt[5]{y^3}-7)/3