What are the solutions to the equation x^5+x^3-2x^2=0 ?

The solutions to the equation x^5+x^3-2x^2=0 are x=0,x=1,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2

Find the zeros of x^5+x^3-2x^2=0

The zeros of x^5+x^3-2x^2=0 are x=0,x=1,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2

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x^{5} + x^{3} - 2 x^{2} = 0

x = 0, x = 1, x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

Solution steps

x^{5} + x^{3} - 2 x^{2} = 0

Factor

x^{5} + x^{3} - 2 x^{2} : x^{2} (x - 1) (x^{2} + x + 2)

x^{2} (x - 1) (x^{2} + x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x^{2} + x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} + x + 2 = 0 : x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

The solutions are

x = 0, x = 1, x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

m^{6} - 1 = 0

x^{4} + 5 x^{3} + 8 x^{2} - 5 x + 1 = 0

(3 x - 2)^{3} = 0

r^{6} = 64

x^{12} = 1

What are the solutions to the equation x^5+x^3-2x^2=0 ?
The solutions to the equation x^5+x^3-2x^2=0 are x=0,x=1,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2
Find the zeros of x^5+x^3-2x^2=0
The zeros of x^5+x^3-2x^2=0 are x=0,x=1,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2