What are the solutions to the equation (x+1)^3=(x+1)^2 ?

The solutions to the equation (x+1)^3=(x+1)^2 are x=0,x=-1

Find the zeros of (x+1)^3=(x+1)^2

The zeros of (x+1)^3=(x+1)^2 are x=0,x=-1

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(x + 1)^{3} = (x + 1)^{2}

x = 0, x = - 1

Solution steps

(x + 1)^{3} = (x + 1)^{2}

Expand

(x + 1)^{3} : x^{3} + 3 x^{2} + 3 x + 1

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

x^{3} + 3 x^{2} + 3 x + 1 = x^{2} + 2 x + 1

Move

1

to the right side

x^{3} + 3 x^{2} + 3 x = x^{2} + 2 x

Move

2 x

to the left side

x^{3} + 3 x^{2} + x = x^{2}

Move

x^{2}

to the left side

x^{3} + 2 x^{2} + x = 0

Factor

x^{3} + 2 x^{2} + x : x (x + 1)^{2}

x (x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0

Solve

x + 1 = 0 : x = - 1

The solutions are

x = 0, x = - 1

x^{3} - 4 x^{2} + 3 x = 0

14 x^{3} + x = x^{2}

x^{4} + x^{2} - 2 = 0

x^{4} - 3 x^{3} - 2 x^{2} + 3 x + 1 = 0

x^{3} - 2 x^{2} + 6 x - 1 = 0

What are the solutions to the equation (x+1)^3=(x+1)^2 ?
The solutions to the equation (x+1)^3=(x+1)^2 are x=0,x=-1
Find the zeros of (x+1)^3=(x+1)^2
The zeros of (x+1)^3=(x+1)^2 are x=0,x=-1