What are the solutions to the equation v^2-12v+21=10 ?

The solutions to the equation v^2-12v+21=10 are v=11,v=1

Find the zeros of v^2-12v+21=10

The zeros of v^2-12v+21=10 are v=11,v=1

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v^{2} - 12 v + 21 = 10

v = 11, v = 1

Solution steps

v^{2} - 12 v + 21 = 10

Move

10

to the left side

v^{2} - 12 v + 11 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 11 = 10

v_{1, 2} = \frac{- ( - 12 ) \pm 10}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 12 ) + 10}{2 \cdot 1}, v_{2} = \frac{- ( - 12 ) - 10}{2 \cdot 1}

v = \frac{- ( - 12 ) + 10}{2 \cdot 1} : 11

v = \frac{- ( - 12 ) - 10}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

v = 11, v = 1

x^{2} + 27 x + 26

4 2^{2}

6 x^{2} - 3 x - 18 = 0

(x^{2} + 2)^{2} - x^{2}

5 \leq x

What are the solutions to the equation v^2-12v+21=10 ?
The solutions to the equation v^2-12v+21=10 are v=11,v=1
Find the zeros of v^2-12v+21=10
The zeros of v^2-12v+21=10 are v=11,v=1