What are the solutions to the equation 8(x^3-x^2+x)+2x(4x^2-4x+1)=30 ?

The solutions to the equation 8(x^3-x^2+x)+2x(4x^2-4x+1)=30 are x\approx 1.45558…

Find the zeros of 8(x^3-x^2+x)+2x(4x^2-4x+1)=30

The zeros of 8(x^3-x^2+x)+2x(4x^2-4x+1)=30 are x\approx 1.45558…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 (x^{3} - x^{2} + x) + 2 x (4 x^{2} - 4 x + 1) = 30

x \approx 1.45558 \dots

Solution steps

8 (x^{3} - x^{2} + x) + 2 x (4 x^{2} - 4 x + 1) = 30

Expand

8 (x^{3} - x^{2} + x) + 2 x (4 x^{2} - 4 x + 1) : 16 x^{3} - 16 x^{2} + 10 x

16 x^{3} - 16 x^{2} + 10 x = 30

Move

30

to the left side

16 x^{3} - 16 x^{2} + 10 x - 30 = 0

Find one solution for

16 x^{3} - 16 x^{2} + 10 x - 30 = 0

using Newton-Raphson:

x \approx 1.45558 \dots

Apply long division:

\frac{16 x ^{3} - 16 x ^{2} + 10 x - 30}{x - 1.45558 \dots} = 16 x^{2} + 7.28935 \dots x + 20.61027 \dots

16 x^{2} + 7.28935 \dots x + 20.61027 \dots \approx 0

Find one solution for

16 x^{2} + 7.28935 \dots x + 20.61027 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 1.45558 \dots

x^{4} - 13 x^{2} + 5 x = 0

x^{3} + 216 = 0

x^{3} - 3 x^{2} - 6 x + 8 = 0

x^{4} - 8 x + 16 = 0

2 y^{4} - 8 y^{2} + 6 = 0

What are the solutions to the equation 8(x^3-x^2+x)+2x(4x^2-4x+1)=30 ?
The solutions to the equation 8(x^3-x^2+x)+2x(4x^2-4x+1)=30 are x\approx 1.45558…
Find the zeros of 8(x^3-x^2+x)+2x(4x^2-4x+1)=30
The zeros of 8(x^3-x^2+x)+2x(4x^2-4x+1)=30 are x\approx 1.45558…