What are the solutions to the equation r^3-7r+6=0 ?

The solutions to the equation r^3-7r+6=0 are r=1,r=2,r=-3

Find the zeros of r^3-7r+6=0

The zeros of r^3-7r+6=0 are r=1,r=2,r=-3

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r^{3} - 7 r + 6 = 0

r = 1, r = 2, r = - 3

Solution steps

r^{3} - 7 r + 6 = 0

Factor

r^{3} - 7 r + 6 : (r - 1) (r - 2) (r + 3)

(r - 1) (r - 2) (r + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r - 1 = 0 or r - 2 = 0 or r + 3 = 0

Solve

r - 1 = 0 : r = 1

Solve

r - 2 = 0 : r = 2

Solve

r + 3 = 0 : r = - 3

The solutions are

r = 1, r = 2, r = - 3

x^{3} + x^{2} = 16 x - 20

x^{3} + 2 x^{2} - x - 2 = 0

x^{3} - 16 = 0

m^{4} + 2 m^{2} + 1 = 0

x^{3} + 2 x = 0

What are the solutions to the equation r^3-7r+6=0 ?
The solutions to the equation r^3-7r+6=0 are r=1,r=2,r=-3
Find the zeros of r^3-7r+6=0
The zeros of r^3-7r+6=0 are r=1,r=2,r=-3