What are the solutions to the equation -2n^3+9n^2-11n+2=0 ?

The solutions to the equation -2n^3+9n^2-11n+2=0 are n=2,n=(5+sqrt(17))/4 ,n=(5-sqrt(17))/4

Find the zeros of -2n^3+9n^2-11n+2=0

The zeros of -2n^3+9n^2-11n+2=0 are n=2,n=(5+sqrt(17))/4 ,n=(5-sqrt(17))/4

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- 2 n^{3} + 9 n^{2} - 11 n + 2 = 0

n = 2, n = \frac{5 + 17}{4}, n = \frac{5 - 17}{4}

Decimal Notation

n = 2, n = 2.28077 \dots, n = 0.21922 \dots

Solution steps

- 2 n^{3} + 9 n^{2} - 11 n + 2 = 0

Factor

- 2 n^{3} + 9 n^{2} - 11 n + 2 : - (n - 2) (2 n^{2} - 5 n + 1)

- (n - 2) (2 n^{2} - 5 n + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n - 2 = 0 or 2 n^{2} - 5 n + 1 = 0

Solve

n - 2 = 0 : n = 2

Solve

2 n^{2} - 5 n + 1 = 0 : n = \frac{5 + 17}{4}, n = \frac{5 - 17}{4}

The solutions are

n = 2, n = \frac{5 + 17}{4}, n = \frac{5 - 17}{4}

x \cdot = x^{3}

x, (3 x + 2 y)^{3} = 1 0^{3}

(x^{2} - 5 x + 4)^{2} - 5 (x^{2} - 5 x) - 18 = 0

x^{3} - 3 x^{2} - 4 x + 8 = 0

x^{3} + x - 5 = 0

What are the solutions to the equation -2n^3+9n^2-11n+2=0 ?
The solutions to the equation -2n^3+9n^2-11n+2=0 are n=2,n=(5+sqrt(17))/4 ,n=(5-sqrt(17))/4
Find the zeros of -2n^3+9n^2-11n+2=0
The zeros of -2n^3+9n^2-11n+2=0 are n=2,n=(5+sqrt(17))/4 ,n=(5-sqrt(17))/4