What are the solutions to the equation 2w^2-3w-65=0 ?

The solutions to the equation 2w^2-3w-65=0 are w= 13/2 ,w=-5

Find the zeros of 2w^2-3w-65=0

The zeros of 2w^2-3w-65=0 are w= 13/2 ,w=-5

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2 w^{2} - 3 w - 65 = 0

w = \frac{13}{2}, w = - 5

Solution steps

2 w^{2} - 3 w - 65 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 65 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 65) = 23

w_{1, 2} = \frac{- ( - 3 ) \pm 23}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 3 ) + 23}{2 \cdot 2}, w_{2} = \frac{- ( - 3 ) - 23}{2 \cdot 2}

w = \frac{- ( - 3 ) + 23}{2 \cdot 2} : \frac{13}{2}

w = \frac{- ( - 3 ) - 23}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

w = \frac{13}{2}, w = - 5

∣ x - 2 ∣ + 2 < 3

\frac{x ^{2 n + 1}}{x ^{2 n - 1}}

6 x - 30

- 4 a + 13 \geq 29 and 10 < 6 a - 14

- \frac{1}{6} (x - 18) + \frac{1}{3} (x + 3) = x + 4

What are the solutions to the equation 2w^2-3w-65=0 ?
The solutions to the equation 2w^2-3w-65=0 are w= 13/2 ,w=-5
Find the zeros of 2w^2-3w-65=0
The zeros of 2w^2-3w-65=0 are w= 13/2 ,w=-5