What are the solutions to the equation 2x^3+7x^2-6x-3=0 ?

The solutions to the equation 2x^3+7x^2-6x-3=0 are x=1,x=(-9+sqrt(57))/4 ,x=(-9-sqrt(57))/4

Find the zeros of 2x^3+7x^2-6x-3=0

The zeros of 2x^3+7x^2-6x-3=0 are x=1,x=(-9+sqrt(57))/4 ,x=(-9-sqrt(57))/4

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2 x^{3} + 7 x^{2} - 6 x - 3 = 0

x = 1, x = \frac{- 9 + 57}{4}, x = \frac{- 9 - 57}{4}

Decimal Notation

x = 1, x = - 0.36254 \dots, x = - 4.13745 \dots

Solution steps

2 x^{3} + 7 x^{2} - 6 x - 3 = 0

Factor

2 x^{3} + 7 x^{2} - 6 x - 3 : (x - 1) (2 x^{2} + 9 x + 3)

(x - 1) (2 x^{2} + 9 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x^{2} + 9 x + 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x^{2} + 9 x + 3 = 0 : x = \frac{- 9 + 57}{4}, x = \frac{- 9 - 57}{4}

The solutions are

x = 1, x = \frac{- 9 + 57}{4}, x = \frac{- 9 - 57}{4}

x^{3} + x - 6 = 0

x^{3} - 3 x + 4 = 0

4 x^{3} - 6 x^{2} - 36 x + 54 = 0

25 + 5 x^{3} = 0

x^{3} + 7 x^{2} + 14 x + 8 = 0

What are the solutions to the equation 2x^3+7x^2-6x-3=0 ?
The solutions to the equation 2x^3+7x^2-6x-3=0 are x=1,x=(-9+sqrt(57))/4 ,x=(-9-sqrt(57))/4
Find the zeros of 2x^3+7x^2-6x-3=0
The zeros of 2x^3+7x^2-6x-3=0 are x=1,x=(-9+sqrt(57))/4 ,x=(-9-sqrt(57))/4