What are the solutions to the equation x^4(x^2+14x+49)=0 ?

The solutions to the equation x^4(x^2+14x+49)=0 are x=0,x=-7

Find the zeros of x^4(x^2+14x+49)=0

The zeros of x^4(x^2+14x+49)=0 are x=0,x=-7

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x^{4} (x^{2} + 14 x + 49) = 0

x = 0, x = - 7

Solution steps

x^{4} (x^{2} + 14 x + 49) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 14 x + 49 = 0

Solve

x^{2} + 14 x + 49 = 0 : x = - 7

The solutions are

x = 0, x = - 7

x^{4} - 2 x^{3} + x = 380

4 x^{3} - 9 x^{2} - 4 x + 6 = 0

m^{3} + 2 m^{2} + m = 0

x^{2} \cdot (x - 3) - x^{2} + 6 x - 9 = 0

z^{4} = - 16

What are the solutions to the equation x^4(x^2+14x+49)=0 ?
The solutions to the equation x^4(x^2+14x+49)=0 are x=0,x=-7
Find the zeros of x^4(x^2+14x+49)=0
The zeros of x^4(x^2+14x+49)=0 are x=0,x=-7