What are the solutions to the equation x^3+2x^2+2x+4=0 ?

The solutions to the equation x^3+2x^2+2x+4=0 are x=-2,x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of x^3+2x^2+2x+4=0

The zeros of x^3+2x^2+2x+4=0 are x=-2,x=sqrt(2)i,x=-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} + 2 x^{2} + 2 x + 4 = 0

x = - 2, x = 2 i, x = - 2 i

Solution steps

x^{3} + 2 x^{2} + 2 x + 4 = 0

Factor

x^{3} + 2 x^{2} + 2 x + 4 : (x + 2) (x^{2} + 2)

(x + 2) (x^{2} + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} + 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 2 = 0 : x = 2 i, x = - 2 i

The solutions are

x = - 2, x = 2 i, x = - 2 i

m^{3} + 8 = 0

2 x^{3} + 3 x^{2} - 1 = 0

x^{3} + x + 1 = 11

4 x (1 - x^{8}) = 0

(1 + r)^{5} = 8

What are the solutions to the equation x^3+2x^2+2x+4=0 ?
The solutions to the equation x^3+2x^2+2x+4=0 are x=-2,x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of x^3+2x^2+2x+4=0
The zeros of x^3+2x^2+2x+4=0 are x=-2,x=sqrt(2)i,x=-sqrt(2)i