What are the solutions to the equation x^4-x^3-9x^2+9x=0 ?

The solutions to the equation x^4-x^3-9x^2+9x=0 are x=0,x=1,x=-3,x=3

Find the zeros of x^4-x^3-9x^2+9x=0

The zeros of x^4-x^3-9x^2+9x=0 are x=0,x=1,x=-3,x=3

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x^{4} - x^{3} - 9 x^{2} + 9 x = 0

x = 0, x = 1, x = - 3, x = 3

Solution steps

x^{4} - x^{3} - 9 x^{2} + 9 x = 0

Factor

x^{4} - x^{3} - 9 x^{2} + 9 x : x (x - 1) (x + 3) (x - 3)

x (x - 1) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = 1, x = - 3, x = 3

x^{4} - 11 x^{2} + 18 = 0

x^{4} - 7 x^{2} + 1 = 0

11 x^{3} - 3 x + 1 = 3 x

x^{4} - x^{3} + x^{2} - x + 1 = 0

x^{3} + 6 x^{2} + 12 x + 8 = 0

What are the solutions to the equation x^4-x^3-9x^2+9x=0 ?
The solutions to the equation x^4-x^3-9x^2+9x=0 are x=0,x=1,x=-3,x=3
Find the zeros of x^4-x^3-9x^2+9x=0
The zeros of x^4-x^3-9x^2+9x=0 are x=0,x=1,x=-3,x=3