What are the solutions to the equation 5x^3+23x^2+20x-12=0 ?

The solutions to the equation 5x^3+23x^2+20x-12=0 are x=-2,x= 2/5 ,x=-3

Find the zeros of 5x^3+23x^2+20x-12=0

The zeros of 5x^3+23x^2+20x-12=0 are x=-2,x= 2/5 ,x=-3

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5 x^{3} + 23 x^{2} + 20 x - 12 = 0

x = - 2, x = \frac{2}{5}, x = - 3

Decimal Notation

x = - 2, x = 0.4, x = - 3

Solution steps

5 x^{3} + 23 x^{2} + 20 x - 12 = 0

Factor

5 x^{3} + 23 x^{2} + 20 x - 12 : (x + 2) (5 x - 2) (x + 3)

(x + 2) (5 x - 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or 5 x - 2 = 0 or x + 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

5 x - 2 = 0 : x = \frac{2}{5}

Solve

x + 3 = 0 : x = - 3

The solutions are

x = - 2, x = \frac{2}{5}, x = - 3

x^{3} - x - 3360 = 0

b^{3} + 2 b^{2} - 10 b - 19 = 0

x, x^{3} + y^{3} = x^{3} y^{3}

x^{25} = x^{0}

x^{4} + (x - 1)^{4} = 97

What are the solutions to the equation 5x^3+23x^2+20x-12=0 ?
The solutions to the equation 5x^3+23x^2+20x-12=0 are x=-2,x= 2/5 ,x=-3
Find the zeros of 5x^3+23x^2+20x-12=0
The zeros of 5x^3+23x^2+20x-12=0 are x=-2,x= 2/5 ,x=-3