What are the solutions to the equation x^3+7x^2-6=0 ?

The solutions to the equation x^3+7x^2-6=0 are x=-1,x=-3+sqrt(15),x=-3-sqrt(15)

Find the zeros of x^3+7x^2-6=0

The zeros of x^3+7x^2-6=0 are x=-1,x=-3+sqrt(15),x=-3-sqrt(15)

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x^{3} + 7 x^{2} - 6 = 0

x = - 1, x = - 3 + 15, x = - 3 - 15

Decimal Notation

x = - 1, x = 0.87298 \dots, x = - 6.87298 \dots

Solution steps

x^{3} + 7 x^{2} - 6 = 0

Factor

x^{3} + 7 x^{2} - 6 : (x + 1) (x^{2} + 6 x - 6)

(x + 1) (x^{2} + 6 x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} + 6 x - 6 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} + 6 x - 6 = 0 : x = - 3 + 15, x = - 3 - 15

The solutions are

x = - 1, x = - 3 + 15, x = - 3 - 15

(x + 1) (x + 2) (x + 3) (x + 4) - 8 = 0

3 x^{3} = 375

x^{3} - 8 x^{2} + 15 x = 0

(1 - x)^{4} + (1 + x)^{4} = 82

x^{4} + 5 x^{2} + 6 = 0

What are the solutions to the equation x^3+7x^2-6=0 ?
The solutions to the equation x^3+7x^2-6=0 are x=-1,x=-3+sqrt(15),x=-3-sqrt(15)
Find the zeros of x^3+7x^2-6=0
The zeros of x^3+7x^2-6=0 are x=-1,x=-3+sqrt(15),x=-3-sqrt(15)