What are the solutions to the equation 20x^4-5x^3-12x^2+3x=0 ?

The solutions to the equation 20x^4-5x^3-12x^2+3x=0 are x=0,x= 1/4 ,x=-sqrt(3/5),x=sqrt(3/5)

Find the zeros of 20x^4-5x^3-12x^2+3x=0

The zeros of 20x^4-5x^3-12x^2+3x=0 are x=0,x= 1/4 ,x=-sqrt(3/5),x=sqrt(3/5)

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20 x^{4} - 5 x^{3} - 12 x^{2} + 3 x = 0

x = 0, x = \frac{1}{4}, x = - \frac{3}{5}, x = \frac{3}{5}

Decimal Notation

x = 0, x = 0.25, x = - 0.77459 \dots, x = 0.77459 \dots

Solution steps

20 x^{4} - 5 x^{3} - 12 x^{2} + 3 x = 0

Factor

20 x^{4} - 5 x^{3} - 12 x^{2} + 3 x : x (4 x - 1) (5 x + 3) (5 x - 3)

x (4 x - 1) (5 x + 3) (5 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x - 1 = 0 or 5 x + 3 = 0 or 5 x - 3 = 0

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

5 x + 3 = 0 : x = - \frac{3}{5}

Solve

5 x - 3 = 0 : x = \frac{3}{5}

The solutions are

x = 0, x = \frac{1}{4}, x = - \frac{3}{5}, x = \frac{3}{5}

2 x^{3} + 2 x^{2} - 8 x + 12 = 0

x^{4} + 16 = 0

n^{3} - 3 n^{2} + 2 n - 336 = 0

x, x^{3} - y^{3} + z^{3} = 4

m^{4} + 2 m^{3} + 3 m^{2} + 2 m + 1 = 0

What are the solutions to the equation 20x^4-5x^3-12x^2+3x=0 ?
The solutions to the equation 20x^4-5x^3-12x^2+3x=0 are x=0,x= 1/4 ,x=-sqrt(3/5),x=sqrt(3/5)
Find the zeros of 20x^4-5x^3-12x^2+3x=0
The zeros of 20x^4-5x^3-12x^2+3x=0 are x=0,x= 1/4 ,x=-sqrt(3/5),x=sqrt(3/5)