What are the solutions to the equation (x^2+1)(x-1)=0 ?

The solutions to the equation (x^2+1)(x-1)=0 are x=i,x=-i,x=1

Find the zeros of (x^2+1)(x-1)=0

The zeros of (x^2+1)(x-1)=0 are x=i,x=-i,x=1

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(x^{2} + 1) (x - 1) = 0

x = i, x = - i, x = 1

Solution steps

(x^{2} + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} + 1 = 0 or x - 1 = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

Solve

x - 1 = 0 : x = 1

The solutions are

x = i, x = - i, x = 1

x^{4} + 8 x^{3} + 3 x - 12 = 0

x^{5} - 2 = 30

(2 x^{2} + 1)^{2} - 4 x^{2} = 0

3 x^{4} + 12 x^{2} = 6 x^{3}

x^{3} + x^{2} = 1

What are the solutions to the equation (x^2+1)(x-1)=0 ?
The solutions to the equation (x^2+1)(x-1)=0 are x=i,x=-i,x=1
Find the zeros of (x^2+1)(x-1)=0
The zeros of (x^2+1)(x-1)=0 are x=i,x=-i,x=1