What are the solutions to the equation 9x^2+25=0 ?

The solutions to the equation 9x^2+25=0 are x= 5/3 i,x=-5/3 i

Find the zeros of 9x^2+25=0

The zeros of 9x^2+25=0 are x= 5/3 i,x=-5/3 i

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9 x^{2} + 25 = 0

x = \frac{5}{3} i, x = - \frac{5}{3} i

Solution steps

9 x^{2} + 25 = 0

Move

25

to the right side

9 x^{2} = - 25

Divide both sides by

9

x^{2} = - \frac{25}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{25}{9}, x = - - \frac{25}{9}

- \frac{25}{9} = \frac{5}{3} i

- - \frac{25}{9} = - \frac{5}{3} i

x = \frac{5}{3} i, x = - \frac{5}{3} i

\frac{57}{3}

\frac{( x - 3 )}{2 x + 1} < 4

\frac{2}{7} - \frac{5}{21} \frac{1}{7}

(\frac{7}{12})^{2}

- 6 x^{2} + 48 x - 72

What are the solutions to the equation 9x^2+25=0 ?
The solutions to the equation 9x^2+25=0 are x= 5/3 i,x=-5/3 i
Find the zeros of 9x^2+25=0
The zeros of 9x^2+25=0 are x= 5/3 i,x=-5/3 i