What are the solutions to the equation 2(x-2)^3+8=136 ?

The solutions to the equation 2(x-2)^3+8=136 are x=6,x=2sqrt(3)i,x=-2sqrt(3)i

Find the zeros of 2(x-2)^3+8=136

The zeros of 2(x-2)^3+8=136 are x=6,x=2sqrt(3)i,x=-2sqrt(3)i

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2 (x - 2)^{3} + 8 = 136

x = 6, x = 23 i, x = - 23 i

Solution steps

2 (x - 2)^{3} + 8 = 136

Move

8

to the right side

2 (x - 2)^{3} = 128

Divide both sides by

2

(x - 2)^{3} = 64

For

g^{3} (x) = f (a)

the solutions are

g (x) = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

Solve

x - 2 = 364 : x = 6

Solve

x - 2 = 364 \frac{- 1 + 3 i}{2} : x = 23 i

Solve

x - 2 = 364 \frac{- 1 - 3 i}{2} : x = - 23 i

The solutions are

x = 6, x = 23 i, x = - 23 i

x^{3} - 11 x^{2} + 32 x - 28 = 0

3 x^{3} - 4 x^{2} + 4 x = 16

(3 - x)^{5} + (x - 5)^{5} = - 32

c, c^{1} c^{2} = r^{1} + r^{2}

x^{7} = 120

What are the solutions to the equation 2(x-2)^3+8=136 ?
The solutions to the equation 2(x-2)^3+8=136 are x=6,x=2sqrt(3)i,x=-2sqrt(3)i
Find the zeros of 2(x-2)^3+8=136
The zeros of 2(x-2)^3+8=136 are x=6,x=2sqrt(3)i,x=-2sqrt(3)i