What are the solutions to the equation r^3-1=0 ?

The solutions to the equation r^3-1=0 are r=1,r=-1/2+(sqrt(3))/2 i,r=-1/2-(sqrt(3))/2 i

Find the zeros of r^3-1=0

The zeros of r^3-1=0 are r=1,r=-1/2+(sqrt(3))/2 i,r=-1/2-(sqrt(3))/2 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{3} - 1 = 0

r = 1, r = - \frac{1}{2} + \frac{3}{2} i, r = - \frac{1}{2} - \frac{3}{2} i

Solution steps

r^{3} - 1 = 0

Move

1

to the right side

r^{3} = 1

For

x^{3} = f (a)

the solutions are

r = 1, r = \frac{- 1 + 3 i}{2}, r = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

r = 1, r = - \frac{1}{2} + \frac{3}{2} i, r = - \frac{1}{2} - \frac{3}{2} i

x^{3} - x^{2} + x + 1 = 0

3 x^{3} - x^{2} - 48 x + 16 = 0

x^{3} - 11 x^{2} + 36 x - 45 = 0

x^{3} - 13 x = 0

(5) x^{3} + x - 2 = 0

What are the solutions to the equation r^3-1=0 ?
The solutions to the equation r^3-1=0 are r=1,r=-1/2+(sqrt(3))/2 i,r=-1/2-(sqrt(3))/2 i
Find the zeros of r^3-1=0
The zeros of r^3-1=0 are r=1,r=-1/2+(sqrt(3))/2 i,r=-1/2-(sqrt(3))/2 i