What are the solutions to the equation x^3=-125 ?

The solutions to the equation x^3=-125 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i

Find the zeros of x^3=-125

The zeros of x^3=-125 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i

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x^{3} = - 125

x = - 5, x = \frac{5}{2} - \frac{5 3}{2} i, x = \frac{5}{2} + \frac{5 3}{2} i

Solution steps

x^{3} = - 125

For

x^{3} = f (a)

the solutions are

Simplify

x = - 5, x = \frac{5}{2} - \frac{5 3}{2} i, x = \frac{5}{2} + \frac{5 3}{2} i

(x + 5) (x^{2} - 4) = 0

(x^{2} - 5 x)^{2} - 7 (x^{2} - 5 x) + 6 = 0

n^{3} - n - 990 = 0

x^{3} - 3 x^{2} - 25 x + 75 = 0

2 x = (35 x^{6}) - 178

What are the solutions to the equation x^3=-125 ?
The solutions to the equation x^3=-125 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i
Find the zeros of x^3=-125
The zeros of x^3=-125 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i