What are the solutions to the equation x^4-5x^3+8x^2+1=0 ?

The solutions to the equation x^4-5x^3+8x^2+1=0 are No Solution for x\in\mathbb{R}

Find the zeros of x^4-5x^3+8x^2+1=0

The zeros of x^4-5x^3+8x^2+1=0 are No Solution for x\in\mathbb{R}

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x^{4} - 5 x^{3} + 8 x^{2} + 1 = 0

No Solution for x \in R

Solution steps

x^{4} - 5 x^{3} + 8 x^{2} + 1 = 0

Find one solution for

x^{4} - 5 x^{3} + 8 x^{2} + 1 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

4 x^{4} - 13 x^{2} + 3 = 0

a^{3} - a^{7} - 5 - 3 = 0

x^{17} = x

x, x^{4} + y^{2} + x^{2} y^{2} + 16 x^{2} - 10 x^{2} y = 0

x, x^{3} d^{2} - x^{2} d^{1} - 3 x y = x^{2}

What are the solutions to the equation x^4-5x^3+8x^2+1=0 ?
The solutions to the equation x^4-5x^3+8x^2+1=0 are No Solution for x\in\mathbb{R}
Find the zeros of x^4-5x^3+8x^2+1=0
The zeros of x^4-5x^3+8x^2+1=0 are No Solution for x\in\mathbb{R}